8X-36x^2=0

Solution for 8X-36x^2=0 equation:

8X-36X^2=0

a = -36; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-36)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-36}=\frac{-16}{-72}
=2/9
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-36}=\frac{0}{-72}
=0
$